3x^2+400x+8000=0

Solution for 3x^2+400x+8000=0 equation:

3x^2+400x+8000=0

a = 3; b = 400; c = +8000;
Δ = b2-4ac
Δ = 4002-4·3·8000
Δ = 64000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{64000}=\sqrt{6400*10}=\sqrt{6400}*\sqrt{10}=80\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(400)-80\sqrt{10}}{2*3}=\frac{-400-80\sqrt{10}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(400)+80\sqrt{10}}{2*3}=\frac{-400+80\sqrt{10}}{6}
$